Is it possible for an object to bouce higher than from where it was dropped?

e.g i drop an object of the suitable material weight and size in perfect conditions from 10 ft onto the best surface to conduct a high bounce.





is it possible for it to bounce and reach 10'1'; or more?Is it possible for an object to bouce higher than from where it was dropped?
It would defy the law of conservation of Energy if it were to go higher then where it was dropped from.





Simple reasoning:


The total mechanical energy that the ball falls with will remain constant throughout it's fall.once it hits the ground, in theory it should be able to bounce back to the same height provided drag(air friction) and losses of energy though heat when it hits the ground are ignored. In reality will never bounce back to the same height however if there is some kind of spring mechanism in the ball , it might come close to it's original height.Is it possible for an object to bouce higher than from where it was dropped?
If you drop a single ball without throwing it, the answer is ';no';, because it would violate the law of energy conservation. But suppose you dropped two balls at the same time, one just above the other. Let's assume they are both perfectly elastic. Suppose they will both have velocity v just before impact with the ground. Also suppose that the bottom ball has mass M and the top ball has mass m. The bottom ball will hit first and rebound with velocity v upward. They collide, and application of the laws of conservation of momentum and energy gives:





Mv -mv = m v1 -Mv2


Mv^2 +mv^2 = m v1^2+M v2^2,





where v1 is the velocity of m after collision and v2 that of M after collision. The solution is:





v1 = (3 M-m) v/(m + M),


v2 = (M-3 m ) v/(m + M)





Note that when M%26gt;m then v1%26gt;v, so that m will rise to a height that is greater than from where it was dropped. In the limit that M/m %26gt;%26gt;1, v1=3 v . Since h=v^2/(2g), it follows that the small ball can rebound to a height that is up-to 9 times the height from which it was dropped!





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The basic reason of the effect is that the small ball gains energy from the big ball, and the big ball loses an equal amount of energy. If you dropped a stack of 3 or more balls, you could make the top ball rebound much higher still. Doing the calculation in my head, I find that with 3 balls, the top ball can approach a rebound height of 49 times its initial height.
Outside the box thinking ... Let's say I drop an object (an egg tapped to a helium balloon, with double sided tape between the egg and balloon) which weighs enough to drop fast enough to break the egg.





I don't think you can really call that a bounce, because it will only return to earth one more time with minimal bounce.


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Another example, would be. If I were to drop a object weighing 16 ounces and it strikes the elevated side of a teeter-totter with a rock weighing 15 ounces with the correct angel/fulcrum setup, I can achieve a result (not the same object - with this example) of multiple bounces.





What I am getting to is, only if every time it ';bounces it looses weight'; - there must be a cost, some sort of loss of energy!
not really cuz the energy it observe by falling down is wasted when in contact with ground and the gravitational pull is a obstract when object is going up. so u can bounce a object but not equal or higher than from where it was dropped.
impossible


coz no material has co efficient of restitution value= 1.





co efficient of restitution=(v-u)/(u'-v')


v,u r velocity before hit the ground(initial and final)


u',v' r velocity after hit the ground(initial and final)
It would be impossible for the ball to bounce to a higher height. If it were to bounce higher than where it fell from, you would be creating energy from nothing. A violation of the laws of thermodynamics.





It can't be done.
In ideal conditions it will bounce to the height it was thrown but it will never be high and that is because of the gravity and friction!!!
no each time you drop something friction from the air slows an object down. Also gravity pulls on something that is falling but it will not go higher than it originally was dropped.
no - unless the 'surface' it bounced from adds energy to the object. (like a blanket toss game where a group of people toss someone in the air)
if you force it then it's possible. but if it free falls any object cannot bounce more than the height it was dropped from .GRAVITY is the reason
Yes it is possible though it depends on what the object is made from.
if you add force to the usual pull of gravity that accts on it while it falls, then it's possible
no, because gravity would pull it down