Sunday, December 27, 2009

How do I calculate how much force is exerted on a 40-kg object with an acceleration of 13 meters/second^2?

The force exerted on an object varies jointly as the mass and acceleration of the object. If a 129-Newton force is exerted on an object of mass 21.5 kg and an acceleration of 6 meters/second^2.How do I calculate how much force is exerted on a 40-kg object with an acceleration of 13 meters/second^2?
Force(In Newtons)=Mass(In Kg) XAcceleration(In m/sec^2)





If the mass = 40kg and the acceleration = 13m/s^2 then the force = 13 X 40, = 520 Newtons.





If the mass =21.5kg and the acceleration = 6m/s^2


then the force = 21.5 X 6 = 129 Newtons.


Which of these was the actual question?How do I calculate how much force is exerted on a 40-kg object with an acceleration of 13 meters/second^2?
force = mass x acceleration





F = ma


F is in Newtons


m is in kg


a is in meters/second^2





so..


F= (40)(13)





From your given, it also works F = (21.5)(6) = 129



No comments:

Post a Comment