If we double the velocity of an object what effect does it have on its kinetic energy?

If you double the height of an object, what effect does that have on potential energy?If we double the velocity of an object what effect does it have on its kinetic energy?
%26gt;The equation for kinetic energy is KE=(1/2)mv^2


m=mass is kilograms


v=velocity is meter per second


KE= kinetic energy is Joules





By doubling the velocity, the kinetic energy would be 4 times as much.


If you triple the velocity, the kinetic energy would be 9 times as much.


If your quadruple the velocity, the energy would be 16 times as much as so on...





%26gt;The equation for (gravitational) potential energy is P=mgh


m= mass is kilograms


g= free-fall acceleration


h= height in meters


P= measured in Joules





By doubling the height of an object, the potential energy would be doubled.


If you triple the height, the energy would be tripled and so on.If we double the velocity of an object what effect does it have on its kinetic energy?
=(KE)1=1/2 mass x (velocity)^2





double the velocity





(K.E)2=1/2 m (2V)^2 ==%26gt; (K.E)2= [1/2 m (2^2)V^2]= 4[1/2 mV^2]


=4(KE)1





if you double the velocity, K.E will be increased 4 times
Ke = 1/2 m v^2


2 Ke = m v^2


2 Ke / m = v^2


square root 2 Ke / M = v


so if v is doubled the Ke will be square root of 2


Pe = m g h


Pe /m g = h


so if the h is doubled then the Pe is also doubled

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