An object is thrown vertically upward with a certain initial velocity in a world where the acceleration due ?

to gravity is 19.6 m/s^2. The height to which it rises is..............that to which the object would rise if thrown upward with the same initial velocity on the Earth. Neglect friction.An object is thrown vertically upward with a certain initial velocity in a world where the acceleration due ?
let's determine the height, h, to which an object would rise if thrown vertically upward with an initial velocity vi, in a world where the acceleration due to gravity is -g (- stands for down)





h = (vf虏 - vi虏)/(2a)





h = (0 - vi虏)/(-2g)





h = vi虏/(2g)





clearly, if g is doubled, then h would become halved





if you want to check:


h1 = vi虏/(2g)


h2 = vi虏/(2(2g))


h2 = vi虏/(4g)





h2/h1 = [vi虏/(4g)] / [vi虏/(2g)]


h2/h1 = 1/2





half